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-4.3x^2+3.9x+2.96=0
a = -4.3; b = 3.9; c = +2.96;
Δ = b2-4ac
Δ = 3.92-4·(-4.3)·2.96
Δ = 66.122
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.9)-\sqrt{66.122}}{2*-4.3}=\frac{-3.9-\sqrt{66.122}}{-8.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.9)+\sqrt{66.122}}{2*-4.3}=\frac{-3.9+\sqrt{66.122}}{-8.6} $
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